Easa Atpl Questions ((free)) -

The options: A) 1.19 B) 1.41 C) 1.32 D) 2.00

The screen flashes:

You remember the trick: Don’t panic. Use the formula: ΔCG = (weight moved × arm change) / total mass. Arm change = 400 – 100 = 300 cm. ΔCG = (150 × 300) / 5700 = 45,000 / 5700 ≈ 7.89 cm aft. Old CG in cm from datum: 22% of MAC means 22% × 200 = 44 cm aft of MAC leading edge. MAC leading edge at station 150, so old CG station = 150 + 44 = 194 cm. New CG station = 194 + 7.89 = 201.89 cm. New CG in % MAC = (201.89 – 150) / 200 × 100 = 51.89 / 200 × 100 ≈ 25.94% ≈ 26% MAC. easa atpl questions

“An aircraft in a level turn at 45° bank angle, with a load factor of 1.414, experiences a stall speed increase of what factor? Assume no other changes.” The options: A) 1

You click it. The screen flashes:

Your finger hovers. Load factor n = 1.414. √1.414 = 1.189. Stall speed increase factor = 1.19. Option A. You click it, and the screen doesn’t immediately turn red. Your heart rate drops from “flaps up overshoot” to “cruise climb.” ΔCG = (150 × 300) / 5700 = 45,000 / 5700 ≈ 7