As they entered the temple, they discovered a large, pyramid-shaped structure with a square base. The side length of the base was 8 meters, and the slant height was 10 meters. The team had to calculate the surface area and volume of the pyramid.
$A = 8^2 + 4 \times \frac{1}{2} \times 8 \times 10 = 64 + 160 = 224$ square meters mathematics 10e myp 5 (extended) third edition pdf
$V = \frac{1}{3} b^2 h$
The students were amazed to find that the second statue was also 4.5 meters tall. As they entered the temple, they discovered a
Solving for h:
The surface area (A) of a pyramid consists of the area of the base and the area of its four triangular faces: As they entered the temple